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fix: hide windows without calling orderOut API

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This commit is contained in:
Alexandre Antonio Juca
2025-01-09 23:14:00 +01:00
committed by Mitchell Hashimoto
parent 4dd9fe5cfd
commit 3a5aecc216
1 changed files with 6 additions and 27 deletions
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33
macos/Sources/App/macOS/AppDelegate.swift
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@ -706,34 +706,13 @@ class AppDelegate: NSObject,
/// Toggles visibility of all Ghosty Terminal windows. When hidden, activates Ghostty as the frontmost application
@IBAction func toggleVisibility(_ sender: Any) {
if let mainWindow = terminalManager.mainWindow {
guard let parent = mainWindow.controller.window else {
Self.logger.debug("could not get parent window")
return
if isVisible {
NSApp.windows.forEach { window in
window.alphaValue = 0.0
}
guard let controller = parent.windowController as? TerminalController,
let primaryWindow = controller.window else {
Self.logger.debug("Could not retrieve primary window")
return
}
// Fetch all terminal windows controlled by BaseTerminalController
for terminalWindow in NSApp.windows.filter({ $0.windowController is BaseTerminalController }) {
if isVisible {
terminalWindow.orderOut(nil)
} else {
primaryWindow.makeKeyAndOrderFront(nil)
primaryWindow.addTabbedWindow(terminalWindow, ordered: .above)
}
}
// If our parent tab group already has this window, macOS added it and
// we need to remove it so we can set the correct order in the next line.
// If we don't do this, macOS gets really confused and the tabbedWindows
// state becomes incorrect.
if let tg = parent.tabGroup, tg.windows.firstIndex(of: parent) != nil {
tg.removeWindow(parent)
} else {
NSApp.windows.forEach { window in
window.alphaValue = 1.0
}
}