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renderer: hide cursor is state explicit asks for invisible cursor
This was a regression. The previous logic would always show the cursor if we were using a non-blinking cursor. But, if the terminal state is explicitly requesting an invisible cursor (mode 25) then we need to hide the cursor.
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@ -531,11 +531,15 @@ pub fn render(
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// Setup our cursor state
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if (self.focused) {
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self.cursor_visible = visible: {
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// If the cursor is explicitly not visible in the state,
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// then it is not visible.
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if (!state.cursor.visible) break :visible false;
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// If the cursor isn't a blinking style, then never blink.
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if (!state.cursor.style.blinking()) break :visible true;
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// Otherwise, adhere to our current state.
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break :visible self.cursor_visible and state.cursor.visible;
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break :visible self.cursor_visible;
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};
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self.cursor_style = renderer.CursorStyle.fromTerminal(state.cursor.style) orelse .box;
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} else {
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@ -731,11 +731,15 @@ pub fn render(
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// Setup our cursor state
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if (self.focused) {
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self.cursor_visible = visible: {
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// If the cursor is explicitly not visible in the state,
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// then it is not visible.
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if (!state.cursor.visible) break :visible false;
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// If the cursor isn't a blinking style, then never blink.
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if (!state.cursor.style.blinking()) break :visible true;
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// Otherwise, adhere to our current state.
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break :visible self.cursor_visible and state.cursor.visible;
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break :visible self.cursor_visible;
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};
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self.cursor_style = renderer.CursorStyle.fromTerminal(state.cursor.style) orelse .box;
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} else {
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@ -1173,6 +1173,10 @@ const StreamHandler = struct {
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}
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pub fn setMode(self: *StreamHandler, mode: terminal.Mode, enabled: bool) !void {
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// Note: this function doesn't need to grab the render state or
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// terminal locks because it is only called from process() which
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// grabs the lock.
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switch (mode) {
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.cursor_keys => {
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self.terminal.modes.cursor_keys = enabled;
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