terminal/kitty: support cells with no diacritics

This commit is contained in:
Mitchell Hashimoto
2024-07-25 19:42:52 -07:00
parent 3549619a64
commit 266033670d

View File

@ -31,58 +31,56 @@ pub const PlacementIterator = struct {
pub fn next(self: *PlacementIterator) ?Placement {
while (self.row) |*row| {
// This row flag is set on rows that have the virtual placeholder
if (!row.rowAndCell().row.kitty_virtual_placeholder) {
self.row = self.row_it.next();
continue;
}
// Our current run. A run is always only a single row. This
// assumption is built-in to our logic so if we want to change
// this later we have to redo the logic; tests should cover;
var run: ?IncompletePlacement = null;
// A row must have graphemes to possibly have virtual placements
// since virtual placements are done via diacritics.
if (row.rowAndCell().row.grapheme) {
// Iterate over our remaining cells and find one with a placeholder.
const cells = row.cells(.right);
for (cells, row.x..) |*cell, x| {
// "row" now points to the top-left pin of the placement.
// We need this temporary state to build our incomplete
// placement.
assert(@intFromPtr(row) == @intFromPtr(&self.row));
row.x = @intCast(x);
// Iterate over our remaining cells and find one with a placeholder.
const cells = row.cells(.right);
for (cells, row.x..) |*cell, x| {
// "row" now points to the top-left pin of the placement.
// We need this temporary state to build our incomplete
// placement.
assert(@intFromPtr(row) == @intFromPtr(&self.row));
row.x = @intCast(x);
// If this cell doesn't have the placeholder, then we
// complete the run if we have it otherwise we just move
// on and keep searching.
if (cell.codepoint() != placeholder) {
if (run) |prev| return prev.complete();
continue;
// If this cell doesn't have the placeholder, then we
// complete the run if we have it otherwise we just move
// on and keep searching.
if (cell.codepoint() != placeholder) {
if (run) |prev| return prev.complete();
continue;
}
// If we don't have a previous run, then we save this
// incomplete one, start a run, and move on.
const curr = IncompletePlacement.init(row, cell);
if (run) |*prev| {
// If we can't append, then we complete the previous
// run and return it.
if (!prev.append(&curr)) {
// Note: self.row is already updated due to the
// row pointer above. It points back at this same
// cell so we can continue the new placements from
// here.
return prev.complete();
}
// TODO: we need to support non-grapheme cells that just
// do continuations all the way through.
assert(cell.hasGrapheme());
// If we don't have a previous run, then we save this
// incomplete one, start a run, and move on.
const curr = IncompletePlacement.init(row, cell);
if (run) |*prev| {
// If we can't append, then we complete the previous
// run and return it.
if (!prev.append(&curr)) {
// Note: self.row is already updated due to the
// row pointer above. It points back at this same
// cell so we can continue the new placements from
// here.
return prev.complete();
}
// append is mutating so if we reached this point
// then prev has been updated.
} else {
// For appending, we need to set our initial values.
var prev = curr;
if (prev.row == null) prev.row = 0;
if (prev.col == null) prev.col = 0;
run = prev;
}
// append is mutating so if we reached this point
// then prev has been updated.
} else {
// For appending, we need to set our initial values.
var prev = curr;
if (prev.row == null) prev.row = 0;
if (prev.col == null) prev.col = 0;
run = prev;
}
}
@ -730,6 +728,33 @@ test "unicode placement: continuation with no col" {
try testing.expect(it.next() == null);
}
test "unicode placement: continuation with no diacritics" {
const alloc = testing.allocator;
var t = try terminal.Terminal.init(alloc, .{ .rows = 5, .cols = 10 });
defer t.deinit(alloc);
t.modes.set(.grapheme_cluster, true);
// Three cells. They'll continue even though they're explicit
try t.printString("\u{10EEEE}");
try t.printString("\u{10EEEE}");
try t.printString("\u{10EEEE}");
// Get our top left pin
const pin = t.screen.pages.getTopLeft(.viewport);
// Should have exactly one placement
var it = placementIterator(pin, null);
{
const p = it.next().?;
try testing.expectEqual(0, p.image_id);
try testing.expectEqual(0, p.placement_id);
try testing.expectEqual(0, p.row);
try testing.expectEqual(0, p.col);
try testing.expectEqual(3, p.width);
}
try testing.expect(it.next() == null);
}
test "unicode placement: run ending" {
const alloc = testing.allocator;
var t = try terminal.Terminal.init(alloc, .{ .rows = 5, .cols = 10 });